Python script to calculate an approximate square root - from scratch

#!/usr/bin/python
def find_close_int_sqrt_and_diff(x):
 ans  = 0
 diff1 = 0
 if x <= 0: return 0,0
 # if x==1: return 1,0
 # if x==2: return 1.414,0
 else:
  for i in range(1,x+1):
   t = i*i
   if t==x: 
    ans = i
    diff1 = 0
    break
   elif t > x: 
    sqrt_int = i-1
    ans = ans + sqrt_int
    tmp_sqr = sqrt_int*sqrt_int
    diff1 = x-tmp_sqr
    break
 return ans, diff1
############################################################################
k=249
l2, d = find_close_int_sqrt_and_diff(k)
while (d>0):
 i, d = find_close_int_sqrt_and_diff(d)
 l2 = l2+i/float(10)

print("the closest sqrt value of %d is %3.2f and the sqr is %3.2f"  %(k, l2, l2*l2))